## Introduction

Typically multiplying two n-digit numbers require n2 multiplications. That is actually how we, humans, multiply numbers. Let’s take a look of an example in case we’ve to multiply two 2-digit numbers.

12 x 15 = ?

OK, we know that the answer is 180 and there are lots of intuitive methods that help us get the right answer. Indeed 12 x 15 it’s just a bit more difficult to calculate than 10 x 15, because multiplying by 10 it really easy – we just add one 0 at the end of the number. Thus 15 x 10 equals 150. But now again on 12 x 15 – we know that this equals 10 x 15 (which is 150) and 2 x 15, which is also very easy to calculate and it is 30. The result of 12×15 will be 150 + 30, which fortunately isn’t difficult to get and equals to 180.

That was easy but in some cases the calculations are a bit more difficult and we need a structured algorithm to get the right answer. What about 65 x 97? That is not so easy as 12 x 15, right?

The algorithm we know from the primary school, described on the diagram below, is well structured and help us multiply two numbers.

We see that even for two-digit numbers this is quite difficult – we have 4 multiplications and some additions.

However so far we know how to multiply numbers, the only problem is that our task becomes very difficult as the numbers grow. If multiplying 65 by 97 was somehow easy, what about

374773294776321 x 222384759707982

It seems almost impossible.

### History

Andrey Kolmogorov
is one of the brightest russian mathematicians of the 20th century. In
1960, during a seminar, Kolmogorov stated that two n-digit numbers can’t
be multiplied with less than n2 multiplications!

Only a week later a 23-year young student called Anatolii Alexeevitch Karatsuba
proved that the multiplication of two n-digit numbers can be computed
with n * lg(3) multiplications with an ingenious divide and conquer
approach.

## Overview

Basically Karatsuba stated that if we have to multiply two n-digit numbers x and y, this can be done with the following operations, assuming that B is the base of and m < n.

First both numbers x and y can be represented as x1,x2 and y1,y2 with the following formula.

x = x1 * B^m + x2 y = y1 * B^m + y2

Obviously now xy will become as the following product.

xy = (x1 * B^m + x2)(y1 * B^m + y2) => a = x1 * y1 b = x1 * y2 + x2 * y1 c = x2 * y2

Finally xy will become:

xy = a * B^2m + b * B^m + c

However a, b and c can be computed at least with four multiplication, which isn’t a big optimization. That is why Karatsuba came up with the brilliant idea to calculate b with the following formula:

b = (x1 + x2)(y1 + y2) - a - c

That make use of only three multiplications to get xy.

Let’s see this formula by example.

47 x 78 x = 47 x = 4 * 10 + 7 x1 = 4 x2 = 7 y = 78 y = 7 * 10 + 8 y1 = 7 y2 = 8 a = x1 * y1 = 4 * 7 = 28 c = x2 * y2 = 7 * 8 = 56 b = (x1 + x2)(y1 + y2) - a - b = 11 * 15 - 28 - 56

Now the thing is that 11 * 15 it’s again a multiplication between 2-digit numbers, but fortunately we can apply the same rules two them. This makes the algorithm of Karatsuba a perfect example of the “divide and conquer” algorithm.

## Implementation

### Standard Multiplication

Typically the standard implementation of multiplication of n-digit numbers require n2 multiplications as you can see from the following PHP implementation.

$x = array(1,2,3,4); $y = array(5,6,7,8); function multiply($x, $y) { $len_x = count($x); $len_y = count($y); $half_x = ceil($len_x / 2); $half_y = ceil($len_y / 2); $base = 10; // bottom of the recursion if ($len_x == 1 && $len_y == 1) { return $x[0] * $y[0]; } $x_chunks = array_chunk($x, $half_x); $y_chunks = array_chunk($y, $half_y); // predefine aliases $x1 = $x_chunks[0]; $x2 = $x_chunks[1]; $y1 = $y_chunks[0]; $y2 = $y_chunks[1]; return multiply($x1, $y1) * pow($base, $half_x * 2) // a + (multiply($x1, $y2) + multiply($x2, $y1)) * pow($base, $half_x) // b + multiply($x2, $y2); // c } // 7 006 652 echo multiply($x, $y);

### Karatsuba Multiplication

Karatsuba replaces two of the multiplications – this of x1 * y2 + x2 * y1 with only one – (x1 + x2)(y1 + y2) and this makes the algorithm faster.

$x = array(1,2,3,4); $y = array(5,6,7,8); function karatsuba($x, $y) { $len_x = count($x); $len_y = count($y); // bottom of the recursion if ($len_x == 1 && $len_y == 1) { return $x[0] * $y[0]; } if ($len_x == 1 || $len_y == 1) { $t1 = implode('', $x); $t2 = implode('', $y); return (int)$t1 * $t2; } $a = array_chunk($x, ceil($len_x/2)); $b = array_chunk($y, ceil($len_y/2)); $deg = floor($len_x/2); $x1 = $a[0]; // 1 $x2 = $a[1]; // 2 $y1 = $b[0]; // 1 $y2 = $b[1]; // 2 return ($a = karatsuba($x1, $y1)) * pow(10, 2 * $deg) + ($c = karatsuba($x2, $y2)) + (karatsuba(sum($x1, $x2), sum($y1, $y2)) - $a - $c) * pow(10, $deg); } // 7 006 652 echo karatsuba($x, $y);

## Complexity

Assuming that we replace two of the multiplications with only one makes the program faster. The question is how fast. Karatsuba improves the multiplication process by replacing the initial complexity of O(n2) by O(nlg3), which as you can see on the diagram below is much faster for big n.

## Application

It’s obvious where the Karatsuba algorithm can be used. It is very efficient when it comes to integer multiplication, but that isn’t its only advantage. It is often used for polynomial multiplications.

Related posts:

- Computer Algorithms: Determine if a Number is Prime
- Computer Algorithms: Linear Search in Sorted Lists
- Computer Algorithms: Binary Search

## Comments

## Mihai Dinca - P... replied on Wed, 2012/05/16 - 2:02am